How do you simplify $(x^-6)/(x^4y^0)$ ?

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Answer 1 · 2015-05-19T17:41:15

Let's remember $3$ important exponent laws:

- $a^-n=1/a^n$

Using the first, we can "cancel" $y$ :

$x^-6/(x^4*1)$

Using the second, we combine the exponents:

$x^(-6-4)=x^-10$

Finally, we know that

$x^-10=1/x^10$

How do you simplify (x^-6)/(x^4y^0)(x^-6)/(x^4y^0)?