How do you simplify $(x^-6w^4)/(w^2z^-1)$ ?

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Answer 1 · 2015-06-12T16:43:45

$color(blue)(x^-6 w^2 z$

$(x^-6w^4)/(w^2z^-1)$

Note:
$color(blue)(a^m / a^n = a^(m-n)$
$color(blue)(1/a^-1 = a^1$

Applying the above mentioned properties to the exponents of $w$ and $z$ respectively.

$= (x^(-6)) . (w^color(blue)((4-2))) . (z^color(blue)(1))$

$= color(blue)(x^-6 w^2 z$

How do you simplify (x^-6w^4)/(w^2z^-1)(x^-6w^4)/(w^2z^-1)?