Question

How do you simplify `(y^2 + 3y - 4)/( 7y^3 + 7y^2 - 14y )`?

Answer 1

See explanation

Explanation:

It is

`(y^2 + 3y - 4)/(7y^3 + 7y^2 - 14y)=(y^2-1+3y-3)/(7y^3-7y+7y^2-7y)= ((y-1)*(y+1+3))/(7y(y^2-1)+7y(y-1))=((y-1)(y+4))/(7y(y-1)(y+1+1))= (y+4)/(7y(y+2))`