How do you sketch the graph of $y = {log}_{2} x - 4$ $y=log_2x-4$ ?

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Answer 1 · 2017-01-01T01:44:56

$x > 0$ $x>0$ . As $x \to 0, y \to - \infty, x = 0 ↓$ $x to 0, y to -oo, x = 0 darr$ is the asymptote.
As #x to oo, y to oo. The graph is inserted.

graph{ (y-log x/log 2 - 4)=0 [-20, 20, -10, 10]}

Use ${log}_{b} a = \frac{{log}_{c} a}{{log}_{c} b}$ $log_b a = log_ca/log_c b$ .

$y = {log}_{2} x - 4 = \frac{log x}{log 2} - 4$ $y = log_2 x-4 =log x/log 2 - 4$ :

The graph, for this form in common logarithm, is inserted.

How do you sketch the graph of y=log_2x-4y=log2x−4y=log_2x-4?