How do you solve $(1.011)^x=2$ ?

Question

2153 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-08T05:00:15

63,36, nearly.

$log (a^n)=- n log a$ .
Equating logarithms, x log 1,011 = log 2.
So, $x = log 2 / log 1.011$ = 63.36, nearly.

Check: $1.011^63.36$ = 2.000015, nearly 2.000, rounded to 4-sd..

How do you solve (1.011)^x=2 (1.011)^x=2 ?