How do you solve $1.05^t = 4.35$ ?

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Answer 1 · 2016-07-19T12:37:18

$t = 30.13$ to 2dp

Take natural log of both sides.

$ln1.05^t = ln4.35$

Using exponent rule of logs, move the t in front:

$tln1.05 = ln4.35$

$t = (ln4.35)/(ln1.05)$

$t = 30.13$ to 2dp

How do you solve 1.05^t = 4.351.05^t = 4.35?