How do you solve ${1.2}^{x} - 1 = 104$ $1.2^x -1= 104$ ?

Question

1599 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-04T10:44:43

$x = 25.526$ $x=25.526$

${1.2}^{x} - 1 = 104$ $1.2^x-1=104$

${1.2}^{x} = 104 + 1$ $1.2^x=104+1$

${1.2}^{x} = 105$ $1.2^x=105$

Taking log on both the sides

$log ({1.2}^{x}) = log (105)$ $\log(1.2^x)=\log(105)$

$x log (1.2) = log (105)$ $x\log(1.2)=\log(105)$

$x = \frac{log (105)}{log (1.2)}$ $x=\frac{\log(105)}{\log(1.2)}$

$x = 25.526$ $x=25.526$

How do you solve 1.2x−1=1041.2^x -1= 104?