How do you solve $(1/4)^(2x)= (1/2)^x$ ?

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Answer 1 · 2018-07-25T18:52:25

$x=0$

Given that

$(1/4)^{2x}=(1/2)^x$

$(1/2^2)^{2x}=(1/2)^x$

$(1/2)^{2\cdot 2x}=(1/2)^x$

$(1/2)^{4x}=(1/2)^x$

Comparing the powers of base $1/2$ on both the sides we get

$4x=2x$

$2x=0$

$x=0$

Answer 2 · 2018-07-25T19:34:27

$x=0$

$(1/4)^(2x)=((1/2)^2)^(2x)=(1/2)^(4x)$

$"For "(1/2)^(4x)=(1/2)^xrArrx=0$

How do you solve (1/4)^(2x)= (1/2)^x(1/4)^(2x)= (1/2)^x?