How do you solve $1 = \frac{x + 3}{- 2 x + 2}$ $1=(x+3)/(-2x+2)$ and find any extraneous solutions?

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Answer 1 · 2018-06-22T11:16:49

$x = - \frac{1}{3}$ $x=-1/3$

It must be

$x \neq 1$ $xne 1$
Multiplying by
$- 2 x + 2$ $-2x+2$
we get

$.2 x + 2 = x + 3$ $.2x+2=x+3$
so
$- 3 x = 1$ $-3x=1$

$x = - \frac{1}{3}$ $x=-1/3$

How do you solve 1=(x+3)/(-2x+2)1=x+3−2x+21=(x+3)/(-2x+2) and find any extraneous solutions?