How do you solve $10^(2-3x)=10^(5x-6)$ ?

Question

2981 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-22T12:06:24

Follow explanation

$2-3x = 5x-6$

because base is the same.

$2+6 = 5x+3x$

$8 = 8x$

$x=1$

Therefore,

$10^-1 = 10^-1$

How do you solve 10^(2-3x)=10^(5x-6)10^(2-3x)=10^(5x-6)?