How do you solve $10^{x} = 30$ $10^x=30$ ?

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Answer 1 · 2015-11-24T14:38:17

$x = {log}_{10} 30 \approx 1.477$ $x=log_10 30 ~~ 1.477$

${log}_{b} p = q$ $log_b p = q$ is equivalent to $b^{q} = p$ $b^q=p$

Therefore
$10^{x} = 30$ $10^x=30$ is equivalent to ${log}_{10} 30 = x$ $log_10 30 = x$

${log}_{10} 30$ $log_10 30$ can be evaluated using a calculator as $\approx 1.477$ $~~1.477$

How do you solve 10^x=3010x=3010^x=30?