How do you solve $12^(2x-8)=15$ ?

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Answer 1 · 2015-09-22T20:43:12

Refer to explanation

We take logarithms on both sides of the equation hence

$12^(2x-8)=15=>(2x-8)=log15/log12=>x=1/2*(log15/log12+8)$

How do you solve 12^(2x-8)=1512^(2x-8)=15?