How do you solve $12/t+t-8=0$ ?

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Answer 1 · 2017-12-01T18:16:38

$t=6 or t=2$

You have equation with a fraction. You can get rid of the denominator by multiplying each term by $t$

$(color(blue)(txx)12)/t + color(blue)(txx)t - color(blue)(txx)(8)=0 xxt$

$12+t^2 -8t =0" "larr$ re-arrange the terms

$t^2 -8t +12 =0" "larr$ factorise

$(t-6)(t-2)=0$

Set each factor equal to $0$

$t-6=0" "rarr t =6$

$t-2=0" "rarr t=2$

How do you solve 12/t+t-8=012/t+t-8=0?