How do you solve $14 ^(7x) = 21$ ?

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Answer 1 · 2016-05-29T23:09:50

$x = log(21)/(7log(14)) ~~ 0.1648$

Take logs of both sides (any base) to get:

$log(21) = log (14^(7x)) = 7x log(14)$

Divide both ends by $7log(14)$ to find:

$x = log(21)/(7log(14)) ~~ 0.1648$

How do you solve 14 ^(7x) = 21 14 ^(7x) = 21?