How do you solve $16 x^{2} - 64 = 0$ $16x^2 - 64=0$ ?

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How do you solve $16 x^{2} - 64 = 0$ $16x^2 - 64=0$ ?

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Answer 1 · 2015-06-15T11:58:26

$x = \pm 2$ $color(blue)(x = +-2$

Explanation:

$16 x^{2} - 64 = 0$ $16x^2 - 64=0$

Taking out the common term $(16)$ $(16)$ :
$16 (x^{2} - 4) = 0$ $16(x^2 - 4)=0$
$x^{2} - 4 = 0$ $x^2 - 4=0$
$x^{2} = 4$ $x^2 =4$
$x = \sqrt{4}$ $x = sqrt4$
$x = \pm 2$ $color(blue)(x = +-2$

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How do you solve $16 x^{2} - 64 = 0$ $16x^2 - 64=0$ ?

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How do you solve $16 x^{2} - 64 = 0$ $16x^2 - 64=0$ ?