How do you solve (2/3)^x=4/9?

1 Answer
Gió
Feb 3, 2017

I got: x=2

Explanation:

I would take thelog in base 2/3 of both sides:
log_(2/3)(2/3)^x=log_(2/3)(4/9)
we use the definition of log to write: log_(2/3)(2/3)^x=x
x=log_(2/3)(4/9)
and again to get: log_(2/3)(4/9)=2

so that finally:
x=2

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