How do you solve $2^{3 x + 5} = 128$ $2^(3x+5)=128$ ?

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Answer 1 · 2018-05-25T16:09:51

$x = \frac{2}{3}$ $x=2/3$

Notice that $128 = 2^{7}$ $128=2^7$ so
$2^{3 x + 5} = 2^{7}$ $2^(3x+5)=2^7$
thus $3 x + 5 = 7$ $3x+5=7$
$3 x = 2$ $3x=2$
$x = \frac{2}{3}$ $x=2/3$

How do you solve 23x+5=1282^(3x+5)=128?