How do you solve 2- 7 - log _ 3 8x = 2? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer mason m Nov 24, 2015 x=1/17496 Explanation: 2-7-log_3 8x=2 -5-log_3 8x=2 -log_3 8x=7 log_3 8x=-7 3^(log_3 8x)=3^-7 8x=1/2187 x=1/17496 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1608 views around the world You can reuse this answer Creative Commons License