How do you solve $2 e^{5 x} = 18$ $2 e ^ (5x) = 18$ ?

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Answer 1 · 2015-10-14T23:00:13

$x = \frac{2 ln (3)}{5}$ $x = (2ln(3))/5$

$2 e^{5 x} = 18$ $2e^(5x) = 18$

$e^{5 x} = 9$ $e^(5x) = 9$

$ln (e^{5 x}) = ln (9)$ $ln(e^(5x)) = ln(9)$

$5 x = 2 ln (3)$ $5x = 2ln(3)$

$x = \frac{2 ln (3)}{5}$ $x = (2ln(3))/5$

How do you solve 2e5x=182 e ^ (5x) = 18?