How do you solve #2-ln(3-x)=0#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Guillaume L. May 9, 2018 #x=3-e²# Explanation: #2-ln(3-x)=0# #D_"f":x<3# (Due to logarithmic) #ln(3-x)=2# #3-x=e²# #x=3-e²# #3-e²<3#, \0/ so here's our answer! Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 5736 views around the world You can reuse this answer Creative Commons License