How do you solve $2 - ln (3 - x) = 0$ $2-ln(3-x)=0$ ?

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Answer 1 · 2018-05-09T14:31:53

$x=3-e²$

$2-ln(3-x)=0$
$D_"f":x<3$ (Due to logarithmic)
$ln(3-x)=2$
$3-x=e²$
$x=3-e²$
$3-e²<3$ ,
\0/ so here's our answer!

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