How do you solve $2 ln ( 3 - x ) - 4 = 0$ ?

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Answer 1 · 2015-06-21T20:57:59

$x=3-e^2=-4.389$

Take the $4$ and $2$ to the right:

$ln(3-x)=4/2=2$

Apply the definition of logarithm:

$log_ax=b ->x=a^b$ here the base is the number $e$ :

$3-x=e^2$

rearranging:
$x=3-e^2=-4.389$

How do you solve 2 ln ( 3 - x ) - 4 = 02 ln ( 3 - x ) - 4 = 0?