How do you solve $2 Log (x - 4) = 4 log 2$ ?

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Answer 1 · 2016-02-25T01:18:59

It is $x=8$

It is

$2 Log (x - 4) = 4 log 2=>log(x-4)^2=log2^4=> (x-4)^2=2^4=>(x-4)=+-4=>x=8 or x=0$

but hence $x>4$ the acceptable solution is $x=8$

How do you solve 2 Log (x - 4) = 4 log 22 Log (x - 4) = 4 log 2?