How do you solve $2^{x} = 0.5$ $2^x=0.5$ ?

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Answer 1 · 2018-03-10T06:00:08

$x = - 1$ $x=-1$

We know that for any $a^{x} = b$ $a^x=b$ , ${log}_{a} b = x$ $log_ab=x$

Here, $a = 2$ $a=2$ and $b = 0.5$ $b=0.5$ . So we take:

${log}_{2} 0.5 = - 1$ $log_2 0.5=-1$

So $x = - 1$ $x=-1$

Answer 2 · 2018-03-10T06:00:36

The answer is $x = - 1$ $x=-1$ .

Rewrite $0.5$ $0.5$ as $\frac{1}{2}$ $1/2$ , then make the exponents equal each other.

$2^{x} = 0.5$ $2^x=0.5$

$2^{x} = \frac{1}{2}$ $2^x=1/2$

$2^{x} = \frac{1}{2^{1}}$ $2^x=1/2^1$

$2^{x} = 2^{- 1}$ $2^x=2^-1$

$2^{x} = 2^{- 1}$ $2^color(red)x=2^color(red)(-1)$

$x = - 1$ $x=-1$

How do you solve 2x=0.52^x=0.5?