How do you solve $2^(x+1) = 3^x$ ?

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How do you solve $2^(x+1) = 3^x$ ?

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Answer 1 · 2016-01-23T01:24:19

$xapprox1.7093$

Explanation:

$2^(x+1)=3^x$
Taking log of both sides
$log2^(x+1)=log3^x$
$implies (x+1)log2=xlog3$
$implies (x+1)xx0.3010=x xx0.4771$
Rearranging we get
$(-0.3010+0.4771)x=0.3010$
$implies x=0.3010/(0.4771-0.3010)$

$xapprox1.7093$

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How do you solve $2^(x+1) = 3^x$ ?

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