How do you solve $2^x=10$ ?

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Answer 1 · 2016-10-11T15:55:28

$x = ln(10)/ln(2)$

Use any base logarithm on both sides. (I will use ln(x)):

$ln(2^x) = ln(10)$

Use the identity ln(a^b) = ln(a)b:

$ln(2)x = ln(10)$

Divide both sides by $ln(2)$ :

$x = ln(10)/ln(2)$

How do you solve 2^x=102^x=10?