How do you solve 2^(x+2) - 2^(x+5)= -7? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Konstantinos Michailidis Sep 9, 2015 We have that 2^(x+2)-2^(x+5)=-7=>2^x(2^2-2^5)=-7=>2^x*(-28)=-7=>2^x=7/28=>2^x=1/4=>2^x=2^(-2)=>x=-2 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1872 views around the world You can reuse this answer Creative Commons License