How do you solve $2^(x+4) = 3^(x-1)$ ?

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Answer 1 · 2018-06-22T10:00:05

$x = 9.5414$

$2 ^(x+4) = 3 ^ (x-1)$

$=>(x + 4) log 2 = (x-1) log 3$

$=> (x+4) * 0.301 = (x-1) * 0.4772$

$x (0.4772 - 0.301) = (4 * 0.301 + 0.4772)$

$0.1762 x = 1.6812$

$x = 1.6812 / 0.1762 = 9.5414$

How do you solve 2^(x+4) = 3^(x-1)2^(x+4) = 3^(x-1)?