How do you solve $2^x= 4^(x+1)$ ?

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Answer 1 · 2015-08-17T12:52:41

$color(blue)(x=-2$

$2^x=4^(x+1)$
We know that $4=2^2$

So the expression can be written as:
$2^x=2^(2*(x+1))$

$2^x=2^(2x+2)$

Now as the bases are equal we equate the exponents to find $x$

$x=2x+2$

$-2=2x-x$

$color(blue)(x=-2$

How do you solve 2^x= 4^(x+1)2^x= 4^(x+1)?