How do you solve $2^{x + 8} = 5$ $2^(x+8)=5$ ?

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How do you solve $2^{x + 8} = 5$ $2^(x+8)=5$ ?

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Answer 1 · 2016-04-16T07:25:44

$2^{x + 8} = 5$ $2^(x+8)=5$
$= {.2}^{x} \cdot 2^{8} = 5$ $=.2^x*2^8=5$
$\Rightarrow 2^{x} = \frac{5}{2^{8}}$ $=>2^x=5/2^8$
$\Rightarrow x log 2 = (log 5 - 8 log 2)$ $=>xlog2=(log5-8log2)$
$x = \frac{log 5}{log 2} - 8$ $x =log5/log2-8$

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How do you solve $2^{x + 8} = 5$ $2^(x+8)=5$ ?

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