How do you solve 23^x=623x=6? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria Apr 9, 2016 x=0.5714x=0.5714 Explanation: 23^x=623x=6 means x=log_(23)6x=log236 As log_ba=loga/logblogba=logalogb x=log6/log23=0.778151/1.361728=0.5714x=log6log23=0.7781511.361728=0.5714 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=819x−4=81? How do you solve logx+log(x+15)=2logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 22log4(x+7)−log4(16)=2? How do you solve 2 log x^4 = 162logx4=16? How do you solve 2+log_3(2x+5)-log_3x=42+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 12808 views around the world You can reuse this answer Creative Commons License