How do you solve $25^(2x+1) =144$ ?

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Answer 1 · 2016-04-27T17:08:35

$x=(log 144/log 25 - 1)/2=(log 12/log 5 - 1)/2$ .

Equate logarithms.

$(2x+1)log 25=log 144$ .

$(2x+1)=log 144/log 25$ .

$x=(log 144/log 25 - 1)/2$

How do you solve 25^(2x+1) =14425^(2x+1) =144?