How do you solve $2cos^2(x)+ 4sin^2(x)=3$ ?

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Answer 1 · 2018-03-24T03:41:55

$x = pi/4 + pi/2n$ , where $n$ is an integer.

Rewrite either completely in sine or completely in cosine.

$2(1- sin^2x) + 4sin^2x= 3$

$2 - 2sin^2x + 4sin^2x= 3$

$2sin^2x = 1$

$sin^2x= 1/2$

$sinx =+- 1/sqrt(2)$

$x = pi/4 + pi/2n$

Hopefully this helps!

How do you solve 2cos^2(x)+ 4sin^2(x)=3 2cos^2(x)+ 4sin^2(x)=3 ?