How do you solve $2e^(0.5x)=45$ ?

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Answer 1 · 2016-07-29T08:00:29

$x=6.227$

As $2e^(0.5x)=45$ , we have

$e^(0.5x)=45/2=22.5$ .

Hence $0.5x=ln22.5$ and

$x=ln22.5/0.5=ln22.5/(1/2)=2xxln22.5=2xx3.1135=6.227$

How do you solve 2e^(0.5x)=452e^(0.5x)=45?