How do you solve $2m - 3n = 6$ and $m = 3 - 2n$ using substitution?

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Answer 1 · 2016-03-15T16:26:53

The solution for the system of equations is:
$color(blue)(n=0$
$color(blue)(m=3$

$2m−3n=6$ ..............equation $(1)$
$color(green)( m=3−2n )$ .................equation $(2)$

Substituting equation $2$ in $1$ :

$2m−3n=6$

$2 * color(green)( (3−2n ))−3n=6$

$6 -4n−3n=6$

$6 -7n=6$

$6 - 6 = 7n$

$7n=0$

$n=0/7$

$color(blue)(n=0$

finding the value of $m$ by substituting the value of $n$ in equation $2$ :

$m=3−2n$

$m=3−2 * 0$

$m=3- 0$

$color(blue)(m=3$

How do you solve 2m - 3n = 62m - 3n = 6 and m = 3 - 2nm = 3 - 2n using substitution?