Question

How do you solve `2sin2x+sqrt3=0` for `0<=x<=360`?

Answer 1

`x=120° or x=150° or x=300° or x=330°`

Explanation:

`sin2x=-sqrt3/2`

`2x=240° or 2x=300° or 2x=600° or 2x=660°`

then

`x=120° or x=150° or x=300° or x=330°`