Question

How do you solve `2sintheta-3costheta=0`?

Answer 1

Answer is `theta=sin^-1(9/13)^(1/2).`

Explanation:

`2sintheta-3costheta=0`
`:.2sintheta=3costheta`
`:.4sin^2theta=9cos^2theta`
`:.4sin^2theta=9*(1-sin^2theta)`
`:.4sin^2theta=9-9sin^2theta`
`:.13sin^2theta=9`
`:.sin^2theta=9/13`
`:.sintheta=sqrt(9/13`
`:.sintheta=(9/13)^(1/2`
`:.theta=sin^-1(9/13)^(1/2).`