How do you solve 2x-7y=62x−7y=6, x+3y=2x+3y=2?

1 Answer
jk.13
Mar 28, 2018

(x,y) = (32/13, -2/13)(x,y)=(3213,−213)

Explanation:

x=2-3yx=2−3y using the second equation, define x in terms of y
2(2-3y)-7y=62(2−3y)−7y=6 plug the above into the first equation
4-6y-7y=64−6y−7y=6 distribute
4-13y=64−13y=6
13y=-213y=−2
y=-2/13y=−213
Going back to the first equation, we can plug this value in for y to achieve x.
x=2-3(-2/13)x=2−3(−213)
x=26/13+6/13x=2613+613

x=32/13x=3213

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