How do you solve 3^(-2x+1) * 3^(-2x-3) = 3^(-x)? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan Mar 15, 2016 x = -2/3 Explanation: Use a^m a^n = a^(m+n). 3^(-2x+1-2x-3) = 3^-x Compare exponents. -4x-2=-x x =-2/3. Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 5114 views around the world You can reuse this answer Creative Commons License