How do you solve $3^(2x+1)=5^200$ ?

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Answer 1 · 2016-04-30T15:10:02

$=>x=(200log5-log3)/(2log3)$

$3^(2x+1)=5^200$

Taking log on both sides we have

$log(3^(2x+1))=log(5^200)$

$=>(2x+1)log(3)=200log(5)$

$=>2xlog3+log3=200log5$

$=>2xlog3=200log5-log3$

$=>x=(200log5-log3)/(2log3)$

How do you solve 3^(2x+1)=5^2003^(2x+1)=5^200?