Question

How do you solve `3.5^x=47.9`?

Answer 1

Apply `log_(3.5)` on both sides. You'll get:
`log_(3.5)3.5^x=log_(3.5)47.9`
That can be written as:
`x=log_(3.5)47.9`
To solve this you can change base to use natural logs, `ln`, as:
`x=(ln(47.9))/(ln(3.5))=3.088`