How do you solve $3 ^(5x) = 27^(2x + 1)$ ?

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Answer 1 · 2016-04-14T03:46:09

Rearrange and take the logarithms to the base 3 of both sides, to yield $x=-3$

Rewrite the right hand side:

$27^(2x+1)=3^(3(2x+1))=3^(6x+3)$

Now the overall equation is:

$3^(5x)=3^(6x+3)$

Taking the log to the base 3 of both sides:

$5x=6x+3$

$x=-3$

How do you solve 3 ^(5x) = 27^(2x + 1)3 ^(5x) = 27^(2x + 1)?