How do you solve $3/7=(x-2)/6$ ?

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Answer 1 · 2017-01-18T01:25:40

$x=32/7$

Solve $3/7=(x-2)/6$

Multiply both sides by $6$ .

$3/7xx6=x-2$

Simplify.

$(3xx6)/7=x-2$

$18/7=x-2$

Multiply both sides by $7$ .

$18=7(x-2)$

Expand.

$18=7x-14$

Add $14$ to both sides.

$18+14=7x$

Simplify.

$32=7x$

Divide both sides by $7$ .

$32/7=x$

Switch sides.

$x=32/7$

How do you solve 3/7=(x-2)/63/7=(x-2)/6?