How do you solve $-3=log_7x$ ?

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Answer 1 · 2015-11-25T18:56:47

$x= 1/343$

$log_b p = q$ means b^q=p#

Therefore $log_7 x = -3$ means $7^(-3)= x$

$x= 1/(7^3) = 1/343$

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