How do you solve $3 = {log}_{x} 125$ $3=log_x125$ ?

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Answer 1 · 2016-04-19T08:22:30

$x = 5$ $x=5$

$3 = {log}_{x} 125$ $3=log_x125$

$3 = {log}_{x} 5^{3}$ $3=log_x 5^3$

$3 = 3 \cdot {log}_{x} 5$ $3=3*log_x 5$

$\frac{3}{3} = {log}_{x} 5$ $3/3=log_x 5$

${log}_{x} 5 = 1$ $log_x 5=1$

$s o; x^{1} = 5$ $so ; x^1=5$

$x = 5$ $x=5$

How do you solve 3=logx1253=log_x125 ?