How do you solve $3^(x+1)=15$ ?

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Answer 1 · 2016-04-27T21:57:15

$x = log 5/log 3 ~~ 1.465$

First note that $3^(x+1) = 3*3^x$ , so we can divide both sides of the equation by $3$ to get:

$3^x = 5$

Taking logs of both sides (any base), we get:

$x log 3 = log 5$

Hence:

$x = log 5 / log 3 ~~ 1.465$

How do you solve 3^(x+1)=153^(x+1)=15?