How do you solve $3^(x+1) * 2^(x-2)= 21$ ?

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Answer 1 · 2015-11-15T02:14:39

Use law of exponents to simplify

$3^x3xx2^x/2^2=21$

$(3xx2)^x(3/4)=21$

$6^x=28$

Next, use the property of logs ...

$xlog6=log28$

$x=log28/log6~~1.86$

hope that helped

How do you solve 3^(x+1) * 2^(x-2)= 213^(x+1) * 2^(x-2)= 21?