How do you solve #3^(x-1)=27#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Dec 30, 2016 #color(green)(x=4)# Explanation: Note that #3^3=3xx3xx3=27# So if #3^(x-1)=27# then #color(white)("XXX") x-1=3# which implies x=4# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 5136 views around the world You can reuse this answer Creative Commons License