How do you solve $3^(x-2)=27$ ?

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Answer 1 · 2015-05-23T09:40:34

$3^(x-2)=27$

27 can be written as $3^3$

$3^(x-2)=3^3$
at this stage exponents can be equated

$x-2 = 3$

$color(blue)( x = 5$ is the solution for the expression.

How do you solve 3^(x-2)=273^(x-2)=27?