How do you solve #3^x=2^(x-1)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Somebody N. Apr 16, 2018 #color(blue)(x~~-1.709511290)# Explanation: #3^x=2^(x-1)# Taking logarithms of both sides: #xln(3)=(x-1)ln(2)# #xln(3)=xln(2)-ln(2)# #xln(3)-xln(2)=-ln(2)# Factor: #x(ln(3)-ln(2))=-ln(2)# #x=(-ln(2))/(ln(3)-ln(2))~~-1.709511290# #color(blue)(x~~-1.709511290)# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1882 views around the world You can reuse this answer Creative Commons License