How do you solve 3^x=log 4? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria Apr 14, 2016 x=-0.4619 Explanation: If 3^x=log4 then log_3(log4)=x or x=log_3(log4)=log(log4)/log3=log(0.60206)/0.4771=(-0.22036)/0.4771=-0.4619 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1378 views around the world You can reuse this answer Creative Commons License